Matematika [tex]{\mathcal Qz}[/tex][tex]{\sf f(x) = x! + x² - 22}[/tex][tex]{\sf f(4)=?}[/tex]​

janellemorissetteulv – April 07, 2023

[tex]{\mathcal Qz}[/tex]
[tex]{\sf f(x) = x! + x² - 22}[/tex]
[tex]{\sf f(4)=?}[/tex]​

• ╰► Penyelesaian ;

f(x) = x! + x² - 22

f(4) = 4! + 4² - 22

f(4) = ( 4.3.2.1 ) + 4² - 22

f(4) = ( 12.2.1 ) + 4² - 22

f(4) = ( 24.1 ) + 4² - 22

f(4) = 24 + ( 4 × 4 ) - 22

f(4) = 24 + 16 - 22

f(4) = 40 - 22

f(4) = 18 ✔️

Jawaban:

18

Penjelasan dengan langkah-langkah:

[tex]{\tt f(x) = x! + x² - 22}[/tex]

[tex]{\sf f(4)=?}[/tex]

[tex] \\ [/tex]

• [tex]{\tt f(4)= 4! + 4² - 22}[/tex]
• [tex]{\tt f(4)= (4 × 3 × 2 × 1) + 4² - 22}[/tex]
• [tex]{\tt f(4)= (12 × 2 × 1) + 4² - 22}[/tex]
• [tex]{\tt f(4)= (24 × 1) + 4² - 22}[/tex]
• [tex]{\tt f(4)= 24 + 4² - 22}[/tex]
• [tex]{\tt f(4)= 24 + (4+4+4+4) - 22}[/tex]
• [tex]{\tt f(4)= 24 + (8+4+4) - 22}[/tex]
• [tex]{\tt f(4)= 24 + (12+4) - 22}[/tex]
• [tex]{\tt f(4)= 24 + 16 - 22}[/tex]
• [tex]{\tt f(4)= 40 - 22}[/tex]
• [tex]{\tt f(4)= 18}[/tex]

[tex] \\ [/tex]

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